1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)s_数学解答

1/2[cos(2x)cos(π/6)+sin(2x)sin(π/6)]-1/2[cos(2x)cos(π/6)-sin(2x)sin(π/6)]=1/2sin(2x)
请问怎么化得1/2sin(2x)?

人气：386 ℃　时间：2020-10-01 04:44:44

解答

前後两式提出1/2相减後结果为2sin(2x)sin(π/3)
sin(π/3)=1/2
所以结果为1/2sin(2x)cos(2x)cos(π/6)消掉，
sin(2x)sin(π/6)+sin(2x)sin(π/6)=2sin(2x)sin(π/6)吗？那sin(π/3)哪来的？那是不小心敲错....是sin(π/6)