f(x)是定义在R上的奇函数,且f(x)=f﹙x-1﹚.求f﹙2010﹚
人气:229 ℃ 时间:2019-08-21 17:17:02
解答
由题知
f(x)是定义在R上的奇函数,
所以,
f(0)=f(-0)
即
f(0)=0
而f(x)=f(x-1)
所以,
f(2010)=f(2009)=f(2008)=.=f(1)=f(0)=0
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